The table shows the grade g on a test when the number of problems in are correct right and equation to model the s i t u a t i o n problem on a test in 10 18 21 g 40 72 84
We can use the given data to form a linear equation to model the situation.
Let the number of problems correct be represented by x, and the grade on the test be represented by y.
From the given data, we have the following points: (10, 40), (18, 72), and (21, 84).
We can use the slope-intercept form of a linear equation, y = mx + b, where m is the slope and b is the y-intercept.
First, let's find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1) = (72 - 40) / (18 - 10) = 32 / 8 = 4
Now that we have the slope, we can use any of the given points and substitute the values into the equation: y - y1 = m(x - x1).
Using the point (10, 40):
y - 40 = 4(x - 10)
Expanding this equation:
y - 40 = 4x - 40
Adding 40 to both sides:
y = 4x
So the equation to model the situation is:
g = 4x