Use any method to locate the zeros of y=−3x2+12x+15 .(1 point)
Responses
There are no zeros.
There are no zeros.
(−1,0)(5,0)
left parenthesis negative 1 comma 0 right parenthesis left parenthesis 5 comma 0 right parenthesis
(0,15)
left parenthesis 0 comma 15 right parenthesis
(1,0)(−5,0)
The zeros of the equation y=−3x^2+12x+15 can be found by setting y equal to zero and solving for x.
Setting y=0, we get:
0 = −3x^2 + 12x + 15
Now, we can try factoring or using the quadratic formula to solve for x.
By factoring:
0 = −3x^2 + 12x + 15
0 = −(x^2 - 4x - 5)
0 = −(x-5)(x+1)
From this, we can see that the zeros are x = 5 and x = -1.
So, the correct answer is:
(−1,0)(5,0)