Use any method to locate the zeros of y=−3x2+12x+15 .(1 point) Responses (1,0)(−5,0) left parenthesis 1 comma 0 right parenthesis left parenthesis negative 5 comma 0 right parenthesis There are no zeros. There are no zeros. (−1,0)(5,0) left parenthesis negative 1 comma 0 right parenthesis left parenthesis 5 comma 0 right parenthesis (0,15)
To find the zeros of the equation y = -3x^2 + 12x + 15, we need to set y equal to zero and solve for x:
0 = -3x^2 + 12x + 15
We can divide the equation by -3 to simplify it:
0 = x^2 - 4x - 5
Now, we can try factoring the quadratic equation:
0 = (x - 5)(x + 1)
Setting each factor equal to zero, we have:
x - 5 = 0 ---> x = 5
x + 1 = 0 ---> x = -1
Therefore, the zeros of the equation y = -3x^2 + 12x + 15 are (5, 0) and (-1, 0).