The volume of a container measures 3,200 in.3 and contains a dozen tennis balls. Each tennis ball has a radius of 2.5 in. How much space in the container is empty? Use 3.14 as an approximation for pi. Round to the nearest whole number, if necessary.
The volume of a tennis ball is represented by the formula V = (4/3)πr^3 where π is pi and r is the radius.
The volume of a tennis ball is V = (4/3)(3.14)(2.5^3) = (4/3)(3.14)(15.625) = 65.453.
The total volume of the 12 tennis balls is V = 12(65.453) = 785.436.
The volume of empty space in the container is 3,200 - 785.436 = <<3200-785.436=2414.564>>2414.564 in^3.
To the nearest whole number, 2,415 in^3 of space in the container are empty. Answer: \boxed{2,415}.