write equation with slope of -1/2 with y intercept of 0,3
A straight line is y = mx + b where m is the slope and b is the y intercept. Just plug in the numbers.
To write the equation of a line with a slope of -1/2 and a y-intercept of (0, 3), you can simply substitute the given values into the equation y = mx + b.
m represents the slope, which is -1/2 in this case. Therefore, the equation becomes y = (-1/2)x + b.
b represents the y-intercept, which is 3 in this case. Substituting it into the equation, we have y = (-1/2)x + 3.
So, the equation of the line is y = (-1/2)x + 3.