how many grams of manganese chloride will be formed if 0.86 moles of manganese oxide react with 48.2 g of hydrogen chloride
To determine the grams of manganese chloride formed in the reaction, we need to first find the molar mass of manganese chloride (MnCl2).
Molar mass of MnCl2 = (atomic mass of Mn) + 2 * (atomic mass of Cl)
= (54.93804 g/mol) + 2 * (35.453 g/mol)
= 54.93804 g/mol + 70.906 g/mol
= 125.84404 g/mol
Now we can use the mole-to-mole ratio between manganese oxide (MnO) and manganese chloride (MnCl2) to determine the moles of manganese chloride formed.
1 mol MnO reacts with 1 mol MnCl2
0.86 moles of MnO will react with 0.86 moles of MnCl2.
Finally, we can convert the moles of MnCl2 to grams using the molar mass of MnCl2.
Mass of MnCl2 = moles of MnCl2 * molar mass of MnCl2
= 0.86 moles * 125.84404 g/mol
= 108.087 g
Therefore, 0.86 moles of manganese oxide will react to form approximately 108.087 grams of manganese chloride.