How many committees of 2 boys and 3 girls can be formed from 8 boys and 10
girls?
To solve this problem, we will use the combination formula.
The number of ways to choose 2 boys out of 8 boys is C(8, 2) = 28.
The number of ways to choose 3 girls out of 10 girls is C(10, 3) = 120.
To find the number of committees that can be formed, we multiply these two results together:
28 * 120 = 3360
So, 3360 committees of 2 boys and 3 girls can be formed from 8 boys and 10 girls.