A carnival game gives variety bags as prizes. The game operator uses 100 balloons and 68 stickers to put into a certain number of bags. How many balloons and how many stickers can go in each bag if they make the greatest number of bags possible so that each bag has the same number of balloons and the same number of stickers?(1 point)
Responses
25 balloons and 17 stickers
25 balloons and 17 stickers
50 balloons and 34 stickers
50 balloons and 34 stickers
4 balloons and 4 stickers
4 balloons and 4 stickers
17 balloons and 25 stickers
To find the greatest number of bags possible with the same number of balloons and stickers, we need to find the greatest common divisor (GCD) of 100 and 68.
The GCD of 100 and 68 is 4.
Therefore, each bag can have 4 balloons and 4 stickers.
So, the correct answer is: 4 balloons and 4 stickers.