when an object is placed 10cm away from a lens; it is found that the formed is 6cm behind the object on the same side of the lens.
Determine the focal lenght of the lens.
solution
1/v + 1/u = 1/f
u=10cm, v=6cm, f=?
6+10/60 = 1/f
70/60 = 1/f
by cross multiply we have
70 x f = 60 x 1
70 x f = 60
f = 60/70 = 6/7 ans.
Pls check if correct
No.
1/10+1/6=1/f
.1+.16666= .26666=1/f
f=1/.26666=?
To solve for the focal length of the lens, we'll use the lens formula:
1/v + 1/u = 1/f
Given that the object distance (u) is 10cm and the image distance (v) is 6cm, we can substitute these values into the formula:
1/6 + 1/10 = 1/f
To simplify the equation, find the least common denominator of 6 and 10, which is 30:
(10 + 6)/60 = 1/f
16/60 = 1/f
Now, cross multiply:
16f = 60
To isolate f, divide both sides of the equation by 16:
f = 60/16 = 15/4
Therefore, the focal length of the lens is 15/4 or 3.75cm.
So, it appears the final answer you calculated is incorrect.