Given the quadratic equation y=5x2+8x+9%0D%0A%0D%0A=%0D%0A5%0D%0A%0D%0A2%0D%0A+%0D%0A8%0D%0A%0D%0A+%0D%0A9%0D%0A, solve for the y-coordinate of the parabola when x=−3%0D%0A%0D%0A=%0D%0A−%0D%0A3%0D%0A.(1 point)%0D%0A(−3%0D%0A−%0D%0A3%0D%0A,)
To find the y-coordinate of the parabola when x=-3, we substitute -3 for x in the quadratic equation:
y = 5x^2 + 8x + 9
y = 5(-3)^2 + 8(-3) + 9
y = 5(9) - 24 + 9
y = 45 - 24 + 9
y = 30
Therefore, the y-coordinate of the parabola when x = -3 is 30.