A silo is a large cylinder container that holds hay a farmer needs to refinish the side of the silo with aluminum The silo has a radius of 4 ft and a height of 30 ft how many square feet of the aluminum does the farmer need to refinish the silo he will not be refinishing the top or bottom of the silo use 3.14 for pi and round your answer to the nearest tenth
The answer is 753.6 by the way
To calculate the surface area of the side of the silo, we will subtract the areas of the top and bottom from the total surface area of the cylinder.
The top and bottom of the silo are circles with a radius of 4 ft each. Therefore, each circle's area is:
Area of one circle = π * (radius)^2
Area of one circle = 3.14 * (4)^2
Area of one circle = 3.14 * 16
Area of one circle ≈ 50.24 square feet
Since there are two circles (top and bottom), the total area of the top and bottom is:
Total area of top and bottom = 2 * Area of one circle
Total area of top and bottom = 2 * 50.24
Total area of top and bottom ≈ 100.48 square feet
The side of the silo is a rectangle wrapped around the cylinder. To find the area of this rectangle, we need to calculate the circumference of the base and multiply it by the height of the silo.
Circumference of the base = 2 * π * radius
Circumference of the base = 2 * 3.14 * 4
Circumference of the base ≈ 25.12 feet
The area of the side of the silo is:
Area of side of silo = Circumference of the base * height
Area of side of silo = 25.12 * 30
Area of side of silo = 753.6 square feet
Finally, the total surface area of the silo (without the top and bottom) is:
Total surface area (excluding top and bottom) = Area of side of silo - Total area of top and bottom
Total surface area (excluding top and bottom) = 753.6 - 100.48
Total surface area (excluding top and bottom) ≈ 653.1 square feet
Therefore, the farmer needs to refinish approximately 653.1 square feet of aluminum on the side of the silo.