Use point-slope form to write the equation of a line that has a slope of 2/3 and passes through (-3, -1). Write your final equation in slope-intercept form.
The point-slope form of a linear equation is given by:
y - y1 = m(x - x1)
Where m is the slope and (x1, y1) are the coordinates of a point on the line.
Given that the slope is 2/3 and the line passes through (-3, -1), we can substitute these values into the point-slope form equation:
y - (-1) = (2/3)(x - (-3))
Simplifying:
y + 1 = (2/3)(x + 3)
To write the equation in slope-intercept form, where y = mx + b, we need to isolate y:
y + 1 = (2/3)(x + 3)
y + 1 = (2/3)x + 2
y = (2/3)x + 2 - 1
y = (2/3)x + 1
Therefore, the equation of the line in slope-intercept form is y = (2/3)x + 1.