Moles of NaOH titrated when 19.26 mL of a 0.12M solution of dilute NaOH
To calculate the moles of NaOH titrated, we first need to determine the volume of the 0.12M NaOH solution used.
Given:
Volume of NaOH solution used = 19.26 mL = 19.26/1000 L = 0.01926 L
Concentration of NaOH solution = 0.12M
We can use the formula:
Moles of solute = Concentration × Volume
Moles of NaOH = 0.12M × 0.01926 L
= 0.00231 moles
Therefore, the moles of NaOH titrated is 0.00231 moles.