Moles of NaOH titrated when 16.28 mL of a 0.12M solution of dilute NaOH
To find the moles of NaOH titrated, we need to use the formula:
moles = concentration × volume
Given that the concentration is 0.12 M and the volume is 16.28 mL (or 0.01628 L), we can plug in the values:
moles = 0.12 M × 0.01628 L
moles = 0.0019536 moles
Therefore, 0.0019536 moles of NaOH were titrated.