Given the following nuclear reaction:
224/88 Ra ----> 4/2 He + A/Z X
Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
a.Ra
b.88
c.228
d.220
e.Beta Decay
f.84
g.Th
h.224
i.86
j.Gamma Decay
k.90
l.Rn
m.Alpha Decay
The nuclear reaction provided is a decay reaction where radium-224 (Ra-224) decays to form a new atom and a helium-4 nucleus (also known as an alpha particle). We can find the properties of the new atom by applying the conservation of mass and charge.
224/88 Ra ----> 4/2 He + A/Z X
1. What is the atomic mass of the new atom?:
The mass number (A) on the left must equal the sum of the mass numbers on the right. The alpha particle has a mass number of 4, so subtracting this from the original mass number of 224 gives us the new atom's mass number:
224 - 4 = 220
Answer: 1 - d.220
2. What is the atomic number of the new atom?:
The atomic number (Z) also must be conserved. The alpha particle has an atomic number of 2, so subtracting this from the original atomic number of 88 gives us the new atom's atomic number:
88 - 2 = 86
Answer: 2 - i.86
3. What is the symbol of the new atom?:
The new atom with an atomic number of 86 corresponds to radon on the periodic table.
Answer: 3 - l.Rn
4. What type of decay is demonstrated here?:
The release of a helium-4 nucleus (alpha particle) in a nuclear reaction signifies alpha decay.
Answer: 4 - m.Alpha Decay
So the completed matches are:
Column A Column B
1. 220 d.220
2. 86 i.86
3. Rn l.Rn
4. Alpha Decay m.Alpha Decay