Sodium undergoes beta decay. Match the missing parts (A, B, and C) of the nuclear equation above to their correct number or symbol:
Column A
1.
A:
A
2.
B:
B
3.
C:
C
Column B
a.24
b.Mg
c.25
d.12
e.10
f.Ne
g.23
Answer:
1. A: d. 12
2. B: f. Ne
3. C: g. 23
For the person above me with no name: are u a bot?
Hmm, let me think about it... Ah, got it! Here's the matching for the missing parts of the nuclear equation:
1. A: c. 25
2. B: b. Mg
3. C: d. 12
So the complete nuclear equation would be:
^23Na → ^25Mg + e^- + ^12C
It's all about chemistry, baby!
The nuclear equation for the beta decay of sodium can be represented as:
Na (A) -> Ne (B) + e (C)
Now let's match the missing parts (A, B, and C) with their correct number or symbol from the options given:
1. A: g (symbol of sodium) - g corresponds to option g, which is 23.
2. B: f (symbol of neon) - f corresponds to option f, which is Ne.
3. C: e (symbol representing electron) - e corresponds to option e, which is 10.
Therefore, the correct matches are:
1. A: 23
2. B: Ne
3. C: 10
To determine the missing parts (A, B, and C) in the nuclear equation for the beta decay of sodium, you need to consider the changes in atomic number and mass number.
In beta decay, the atomic number increases by 1, while the mass number remains the same. Sodium (symbol: Na) has an atomic number of 11 and a mass number of approximately 23.
Based on this information, we can match the missing parts:
A: A = 1 (increase in atomic number)
B: B = c.25 (unchanged mass number)
C: C = g.23 (original atomic number of sodium)
Therefore, the correct match is:
1. A: a
2. B: c
3. C: g
So, the final nuclear equation for the beta decay of sodium is:
^23Na -> ^23Mg + e^0_ -1
Note: The missing parts of A, B, and C can vary for different isotopes, but for sodium specifically, this is the matching configuration.