Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?
(1 point)
Responses
Barium has fewer valence electrons, but they are in a higher energy level.
Barium has more valence electrons, and they are in a higher energy level.
Francium has fewer valence electrons, but they are in a higher energy level.
Francium has more valence electrons, and they are in a higher energy level.
To compare the valence electrons of francium (Fr) and barium (Ba), we must first look at their positions within the periodic table. Francium belongs to Group 1 (alkali metals), and barium is in Group 2 (alkaline earth metals). The group number generally indicates how many valence electrons each element in that group has.
Francium (Fr) has one valence electron because it is an alkali metal, and it is located at the bottom of this group, implying it's in the seventh period (the largest energy level).
Barium (Ba) has two valence electrons because it is an alkaline earth metal, and it is situated in the sixth period, just above francium in the periodic table.
Given this information, the correct comparison would be:
Barium has more valence electrons, but they are in a lower energy level.
However, this comparison is not listed in the provided options. The options contain an error, as none of them correctly describe the relationship between the valence electrons of francium and barium. If we had to choose from the incorrect options, the closest one to being accurate would be:
Barium has more valence electrons, and they are in a higher energy level.
This option is incorrect regarding the energy level (as francium's valence electrons are in a higher energy level than those of barium), but it accurately states that barium has more valence electrons than francium.
what is the correct answer
Apologies for the confusion in the previous message. I'll clarify the comparison between the valence electrons of francium (Fr) and barium (Ba).
Francium (Fr) is in Group 1 of the periodic table and has 1 valence electron in its outermost shell, which is the seventh energy level (n=7), as it is in the seventh period.
Barium (Ba) is in Group 2 of the periodic table and has 2 valence electrons in its outermost shell, which is the sixth energy level (n=6), as it is in the sixth period.
Based on this, the statement that correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba) is:
Francium has fewer valence electrons, but they are in a higher energy level.
This means francium has 1 valence electron in the 7th energy level (n=7), while barium has 2 valence electrons in the 6th energy level (n=6). Thus, francium's valence electrons are at a higher principal quantum number shell compared to barium's.
To compare the valence electrons for atoms of francium (Fr) and barium (Ba), we need to look at their positions in the periodic table.
Francium is located in the first group (or column) of the periodic table, specifically in Group 1. Elements in Group 1, also known as the alkali metals, have one valence electron.
Barium, on the other hand, is located in the second group (or column) of the periodic table, specifically in Group 2. Elements in Group 2, known as the alkaline earth metals, have two valence electrons.
Therefore, the correct statement is: Francium has one valence electron, and it is in a higher energy level, while barium has two valence electrons, and they are in a higher energy level.