A shortstop is standing in the base path between second and third base when she fields the ball. She is 25 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.
(1 point)
The distance the shortstop needs to throw the ball is the diagonal of the square field. Using the Pythagorean theorem, we can find this distance.
Let's call the distance she needs to throw the ball "x".
Using the Pythagorean theorem:
x^2 = (25 feet)^2 + (25 feet)^2
x^2 = 625 feet^2 + 625 feet^2
x^2 = 1250 feet^2
Taking the square root of both sides:
x = √1250 feet
x ≈ 35.4 feet
Therefore, the shortstop needs to throw the ball approximately 35.4 feet.