Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
In three to five sentences, explain how you can find the mass of the ammonia. Then, given R=0.0821L⋅atmmol⋅K, calculate the mass.
To find the mass of ammonia, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Rearranging the equation, we can solve for n (number of moles): n = PV/RT. Once we have the number of moles, we can multiply it by the molar mass of ammonia (17 g/mol) to find the mass.
Using the given values: P = 1.2 atm, V = 3.7 L, T = 290 K, and R = 0.0821 L⋅atmmol⋅K, we can substitute them into the equation and solve for n: n = (1.2 atm * 3.7 L) / (0.0821 L⋅atmmol⋅K * 290 K) ≈ 0.179 mol.
Finally, we can calculate the mass of the ammonia by multiplying the number of moles by the molar mass: 0.179 mol * 17 g/mol ≈ 3.043 g.