Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 15 in increments of 1 and y-axis ranging from 0 to 75 in increments of 5. Multiple points are plotted and a line points upward to the right with an arrowhead on the top.
The line passes approximately through left parenthesis 0 comma 25 right parenthesis, left parenthesis 1 comma 30 right parenthesis, left parenthesis 2 comma 35 right parenthesis, left parenthesis 7 comma 60 right parenthesis, and left parenthesis 10 comma 75 right parenthesis. 5 points are plotted to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y=
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To find the equation of the trend line, we can find the slope using the formula:
m = (change in y) / (change in x)
Using the points (0, 25) and (10, 75), we have:
(change in y) = 75 - 25 = 50
(change in x) = 10 - 0 = 10
So the slope, m, is 50/10 = 5.
Next, we can find the y-intercept by substituting the coordinates of one of the points into the slope-intercept form equation (y = mx + b) and solving for b.
Using the point (0, 25), we have:
25 = 5(0) + b
25 = b
Therefore, the y-intercept, b, is 25.
Putting it all together, the equation of the trend line in slope-intercept form is:
y = 5x + 25