A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75−16t2 , where t is time in seconds. (1 point)
To find the number of feet the diver is above the ocean in 2 seconds, we substitute t=2 into the formula 75-16t^2.
75-16(2^2)
75-16(4)
75-64
= 11 feet.
Therefore, the diver is 11 feet above the ocean after 2 seconds. Answer: \boxed{11}.