A shortstop is standing in the base path between second and third base when she fields the ball. She is 30 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth. (1 point)
The distance the shortstop needs to throw the ball is the hypotenuse of a right triangle, with the distance from second base to first base as one leg, and the distance from the shortstop to second base as the other leg.
Using the Pythagorean theorem, we can find the distance the shortstop needs to throw the ball:
distance^2 = (distance from second base to first base)^2 + (distance from shortstop to second base)^2
distance^2 = 30^2 + 90^2
distance^2 = 900 + 8100
distance^2 = 9000
distance = √9000
distance ≈ 94.9 feet
Therefore, the shortstop needs to throw the ball approximately 94.9 feet to reach first base.