Jada has challenged herself to do at least 100 full push-ups this week on Sunday. She does 30 push-ups. Her arms are sore so she decides to do fewer push-ups on the remaining days of the week. She wants to do the same number of push-ups each day for the rest of the week, right and solve an inequality for the number of push-ups Jada needs to do each day for the rest of the week to meet her goal of 100 push-ups which answer choice best interprets the solution in the context of the problem.

Let's say Jada wants to do x push-ups each day for the rest of the week. Since there are 6 remaining days in the week (excluding Sunday), the total number of push-ups she will do is 6x.

Since she has already done 30 push-ups on Sunday, the total number of push-ups she will do this week is 30 + 6x.

To meet her goal of 100 push-ups, we can set up the inequality:

30 + 6x ≥ 100

Simplifying the inequality, we have:

6x ≥ 70

Dividing both sides of the inequality by 6, we get:

x ≥ 11.67

Since we can't have a fraction of a push-up, the smallest whole number that is greater than or equal to 11.67 is 12. Therefore, Jada needs to do at least 12 push-ups each day for the rest of the week to meet her goal of 100 push-ups.

Therefore, the answer choice that best interprets the solution in the context of the problem is: "Jada needs to do at least 12 push-ups each day for the rest of the week."