The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base round the answer to the nearest tenth.
thats wrong
still wrong
thats the same thing you put last time
nope
the correct answer is 591.6.
We can use the Pythagorean theorem to find the length of the edge of the square base. Let's call it $x$.
The slant height, height, and half of the edge of the square base form a right triangle. Using the Pythagorean theorem, we have:
$x^2 = (436.5)^2 - (321)^2$
$x^2 = 190490.25 - 103041$
$x^2 = 87449.25$
$x \approx \sqrt{87449.25} \approx 295.5$
Therefore, the length of the edge of the square base is approximately 295.5 ft.
I apologize for the mistake. Let's correct it:
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
The slant height, height, and half of the edge of the square base form a right triangle. We have:
$x^2 = (436.5)^2 - (321)^2$
$x^2 = 190490.25 - 103041$
$x^2 = 87449.25$
$x = \sqrt{87449.25} = 295.7$
Therefore, the length of the edge of the square base is approximately 295.7 ft, rounded to the nearest tenth.
Apologies for the incorrect response. Let's correct it:
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
The slant height, height, and half of the edge of the square base form a right triangle. We have:
$x^2 = (436.5)^2 - (321)^2$
$x^2 = 190490.25 - 103041$
$x^2 = 87449.25$
$x = \sqrt{87449.25} \approx 295.7$
Therefore, the length of the edge of the square base is approximately 295.7 ft, when rounded to the nearest tenth.
Apologies for the repeated incorrect response. Let's calculate it again.
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
We know that the slant height is 436.5 ft and the height is 321 ft.
Using Pythagorean theorem, we have:
$x^2 = 436.5^2 - 321^2$
$x^2 = 190622.25 - 103041$
$x^2 = 87581.25$
$x = \sqrt{87581.25} \approx 295.9$
Therefore, the length of the edge of the square base is approximately 295.9 ft, rounded to the nearest tenth.
I apologize for the repeated mistakes. Let's calculate it again.
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
We know that the slant height is 436.5 ft and the height is 321 ft.
Using Pythagorean theorem, we have:
$x^2 = 436.5^2 - 321^2$
$x^2 = 190622.25 – 103041$
$x^2 = 87581.25$
$x \approx \sqrt{87581.25} \approx 295.8$
Therefore, the length of the edge of the square base is approximately 295.8 ft, rounded to the nearest tenth.