The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base round the answer to the nearest tenth.
thats wrong
still wrong
thats the same thing you put last time
nope
the correct answer is 591.6.
We can use the Pythagorean theorem to find the length of the edge of the square base. Let's call it $x$.
The slant height, height, and half of the edge of the square base form a right triangle. Using the Pythagorean theorem, we have:
$x^2 = (436.5)^2 - (321)^2$
$x^2 = 190490.25 - 103041$
$x^2 = 87449.25$
$x \approx \sqrt{87449.25} \approx 295.5$
Therefore, the length of the edge of the square base is approximately 295.5 ft.
I apologize for the mistake. Let's correct it:
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
The slant height, height, and half of the edge of the square base form a right triangle. We have:
$x^2 = (436.5)^2 - (321)^2$
$x^2 = 190490.25 - 103041$
$x^2 = 87449.25$
$x = \sqrt{87449.25} = 295.7$
Therefore, the length of the edge of the square base is approximately 295.7 ft, rounded to the nearest tenth.
Apologies for the incorrect response. Let's correct it:
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
The slant height, height, and half of the edge of the square base form a right triangle. We have:
$x^2 = (436.5)^2 - (321)^2$
$x^2 = 190490.25 - 103041$
$x^2 = 87449.25$
$x = \sqrt{87449.25} \approx 295.7$
Therefore, the length of the edge of the square base is approximately 295.7 ft, when rounded to the nearest tenth.
Apologies for the repeated incorrect response. Let's calculate it again.
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
We know that the slant height is 436.5 ft and the height is 321 ft.
Using Pythagorean theorem, we have:
$x^2 = 436.5^2 - 321^2$
$x^2 = 190622.25 - 103041$
$x^2 = 87581.25$
$x = \sqrt{87581.25} \approx 295.9$
Therefore, the length of the edge of the square base is approximately 295.9 ft, rounded to the nearest tenth.
I apologize for the repeated mistakes. Let's calculate it again.
To find the length of the edge of the square base, we can use the Pythagorean theorem. Let's call it $x$.
We know that the slant height is 436.5 ft and the height is 321 ft.
Using Pythagorean theorem, we have:
$x^2 = 436.5^2 - 321^2$
$x^2 = 190622.25 – 103041$
$x^2 = 87581.25$
$x \approx \sqrt{87581.25} \approx 295.8$
Therefore, the length of the edge of the square base is approximately 295.8 ft, rounded to the nearest tenth.
To find the length of the edge of the square base of the Pyramid in Memphis, Tennessee, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).
In this case, the height of the pyramid acts as the height of the right triangle (a), and the slant height of the pyramid acts as the hypotenuse (c). We need to find the length of the edge of the square base (b).
Using the Pythagorean theorem, we can set up the equation:
a^2 + b^2 = c^2
Substituting the given values:
(321 ft.)^2 + b^2 = (436.5 ft.)^2
Simplifying:
103,041 ft^2 + b^2 = 190,522.25 ft^2
Next, subtract 103,041 ft^2 from both sides:
b^2 = 190,522.25 ft^2 - 103,041 ft^2
b^2 = 87,481.25 ft^2
Now, take the square root of both sides to find b:
√(b^2) = √(87,481.25 ft^2)
b = √87,481.25 ft
Using a calculator, the approximate value of b is 295.2 ft (rounded to the nearest tenth).
Therefore, the length of the edge of the square base of the Pyramid in Memphis, Tennessee, rounded to the nearest tenth, is 295.2 ft.