Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
In six sentences, explain how you can find the mass of the ammonia. Then, given R=0.0821L⋅atmmol⋅K
, calculate the mass.
(4 points)
To find the mass of the ammonia gas, we need to apply the ideal gas law equation, which states PV = nRT. In this equation, P represents the pressure, V represents the volume, n represents the number of moles, R is the ideal gas constant, and T represents the temperature in Kelvin.
First, we can calculate the number of moles of ammonia gas using the ideal gas law equation. Rearranging the equation, we have n = PV/RT. Plugging in the values, n = (1.2 atm * 3.7 L) / (0.0821 L⋅atmmol⋅K * 290K).
Next, we can multiply the number of moles by the molar mass of ammonia to find the mass. The molar mass of ammonia is given as approximately 17 grams per mole. So, mass = n * molar mass.
We substitute the value obtained in the previous calculation for n, and we find mass = [(1.2 atm * 3.7 L) / (0.0821 L⋅atmmol⋅K * 290K)] * 17 grams/mole.
Calculating this expression, we can find the mass of the ammonia in grams.