Scientists heats 30 grams of calcium carbonate CaCO3 in a chemical reaction shown what is the total mass of the product
To determine the total mass of the product in this chemical reaction, we need to know the chemical equation of the reaction.
However, assuming the reaction is the decomposition of calcium carbonate into calcium oxide (CaO) and carbon dioxide (CO2), the balanced chemical equation is:
CaCO3 -> CaO + CO2
According to the equation, 1 mole of calcium carbonate yields 1 mole of calcium oxide and 1 mole of carbon dioxide.
To find the molar mass of calcium carbonate, we sum up the atomic masses of each element:
Ca: 40.08 g/mol
C: 12.01 g/mol
O: 16.00 g/mol (multiplying by 3 due to three oxygen atoms)
Total molar mass of CaCO3 = (40.08 + 12.01 + (16.00 * 3)) g/mol = 100.09 g/mol
Since we have 30 grams of calcium carbonate, we can find the number of moles of calcium carbonate by dividing the mass by the molar mass:
30 g / 100.09 g/mol = 0.2999 mol (approximately 0.3 mol)
Since the balanced equation shows a 1:1 ratio between calcium carbonate and calcium oxide, we will have the same number of moles of calcium oxide as calcium carbonate:
0.3 mol of CaO
To find the molar mass of calcium oxide, we sum up the atomic masses of calcium and oxygen:
Ca: 40.08 g/mol
O: 16.00 g/mol
Molar mass of CaO = 40.08 g/mol + 16.00 g/mol = 56.08 g/mol
Now we can calculate the mass of calcium oxide by multiplying the number of moles (0.3 mol) by the molar mass (56.08 g/mol):
0.3 mol * 56.08 g/mol = 16.82 g
Therefore, the total mass of the product (calcium oxide) is 16.82 grams.