A scientists heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown what is the total mass of the products
The chemical reaction equation for the heating of calcium carbonate is:
CaCO3(s) → CaO(s) + CO2(g)
According to the equation, 1 mole of calcium carbonate (CaCO3) will produce 1 mole of calcium oxide (CaO) and 1 mole of carbon dioxide (CO2).
The molar mass of CaCO3 is:
40.08 g/mol (Ca) + 12.01 g/mol (C) + 3(16.00 g/mol) (O) = 100.09 g/mol
Since 1 mole of CaCO3 has a mass of 100.09 g, the 30 grams of calcium carbonate is equivalent to:
30 g / 100.09 g/mol = 0.2999 moles
Since the reaction is balanced, it means 0.2999 moles of CaCO3 will produce 0.2999 moles of CaO and 0.2999 moles of CO2.
The molar mass of CaO is:
40.08 g/mol (Ca) + 16.00 g/mol (O) = 56.08 g/mol
So, the mass of calcium oxide (CaO) produced is:
0.2999 moles x 56.08 g/mol = 16.81 grams
The molar mass of CO2 is:
12.01 g/mol (C) + 2(16.00 g/mol) (O) = 44.01 g/mol
So, the mass of carbon dioxide (CO2) produced is:
0.2999 moles x 44.01 g/mol = 13.20 grams
Therefore, the total mass of the products (CaO + CO2) is:
16.81 grams (CaO) + 13.20 grams (CO2) = 30.01 grams.
The chemical reaction you provided is incomplete, as the products are not specified. However, I will assume that the complete reaction is:
CaCO3(s) → CaO(s) + CO2(g)
According to the balanced equation, 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2. To calculate the total mass of the products, we need to find the molar mass of CaO and CO2.
The molar mass of CaO (calcium oxide) is:
Ca: 40.08 g/mol
O: 16.00 g/mol
So, the molar mass of CaO is:
40.08 g/mol + 16.00 g/mol = 56.08 g/mol
The molar mass of CO2 (carbon dioxide) is:
C: 12.01 g/mol
O: 16.00 g/mol
So, the molar mass of CO2 is:
12.01 g/mol + (16.00 g/mol * 2) = 44.01 g/mol
Since 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2, we can say that 1 mole of CaCO3 has a total mass of:
56.08 g/mol + 44.01 g/mol = 100.09 g/mol
Therefore, if you heat 30 grams of CaCO3, the total mass of the products would be approximately 30 grams since the total mass is conserved in a chemical reaction.