Look at the following free body diagram
Ff = 25 N
What is the net force on this object?
O O
a
b
с
d 35 N to the right
I
20 N to the left
10 N up
10 N down
Fn = 40 N
Fapplied = 60 N
Fg = 40 N
dont lisson to the robot he is wrong it is not 165 N
To determine the net force on the object based on the given free body diagram, we need to calculate the vector sum of all the forces acting on the object.
First, let's identify the forces acting on the object:
1. Ff = 25 N: This force represents the force of friction acting on the object. It is not relevant to finding the net force since it is already included in the given free body diagram.
2. Fg = 40 N: This represents the force of gravity acting on the object. Gravity always pulls objects downward, so this force points downwards.
3. Fn = 40 N: This is the normal force exerted by the surface supporting the object. The normal force is always perpendicular to the surface and acts in the opposite direction of any force pushing the object into the surface.
4. Fapplied = 60 N: This represents an applied force acting on the object. The direction is not specified, so we have to determine the direction based on the other given forces.
5. 20 N to the left: This represents a force acting to the left. Since the given forces only have right or down as options, we can assume this as the applied force since it points in the opposite direction of the given applied force value.
6. 10 N up: This represents a force acting upward.
7. 10 N down: This represents a force acting downward.
Now, let's calculate the net force by finding the vector sum of all the forces:
First, calculate the horizontal forces:
- Fapplied = 60 N (to the left)
- 20 N to the left
Net horizontal force = Fapplied + 20 N = 60 N + (-20 N) = 40 N to the left (opposite the direction of Fapplied)
Next, calculate the vertical forces:
- Fg = 40 N (downward)
- 10 N down
- 10 N up
Net vertical force = Fg + 10 N + (-10 N) = 40 N + (-10 N) + 10 N = 40 N (downward)
Finally, combine the horizontal and vertical forces to find the net force:
Net force = √((Net horizontal force)^2 + (Net vertical force)^2)
= √((-40 N)^2 + (40 N)^2)
= √(1600 N^2 + 1600 N^2)
= √(3200 N^2)
= √(3200 N^2)
≈ 56.57 N
Therefore, the net force on the object is approximately 56.57 N and its direction is to the left.
The net force on the object can be found by adding up all the individual forces acting on it.
Net force = Fapplied + Ff + Fg + Fn
Given the values:
Fapplied = 60 N
Ff = 25 N
Fg = 40 N
Fn = 40 N
Net force = 60 N + 25 N + 40 N + 40 N = 165 N
Therefore, the net force on the object is 165 N.
Apologies for the incorrect response. Let's recalculate the net force by correcting the previous miscalculation.
Net force = Fapplied + Ff + Fg + Fn
Given the values:
Fapplied = 60 N
Ff = 25 N
Fg = 40 N
Fn = 40 N
Net force = 60 N + 25 N + 40 N + 40 N = 165 N
The correct result is indeed 165 N.