In the free-body diagram, the magnitude of the normal force is 35 N, the friction force is 15 N, and the net force is 70 N. What is the magnitude of the applied force? Explain how you came to your answer in one to two sentences.
To find the magnitude of the applied force, we need to consider the equation for net force (F_net = F_applied - F_friction) and given that F_friction is 15 N and F_net is 70 N, we can rearrange the equation to solve for F_applied: F_applied = F_net + F_friction = 70 N + 15 N = 85 N. Thus, the magnitude of the applied force is 85 N.
The magnitude of the applied force is 50 N. This can be determined by subtracting the sum of the normal force and the friction force from the net force, since the applied force is the only remaining force acting on the object.
To find the magnitude of the applied force, we need to use Newton's second law, which states that the net force on an object is equal to the product of its mass and acceleration. Since no other forces are mentioned, we can assume that the net force is the sum of the normal force, friction force, and the applied force. So, by subtracting the sum of the normal force and friction force from the net force, we can find the magnitude of the applied force. In this case, the applied force would be 70 N - 35 N - 15 N = 20 N.
