Solve the system of two equations using elimination with multiplication
4x-6y= -48
-2x+4y=30
1.(-33,-9)
2. (3,9)
3.(-3,6)
4. (-21,-6)
To solve the system of equations using elimination with multiplication, we need to eliminate one variable by multiplying one or both of the equations by a scalar.
Let's start by eliminating the x variable.
First, let's multiply the second equation by 2 to match the coefficients of x in both equations:
-2x + 4y = 30 *2
-4x + 8y = 60
Now, we can add this equation to the first equation to eliminate the x variable:
(4x - 6y) + (-4x + 8y) = -48 + 60
2y = 12
y = 6
Now, substitute the value of y into either equation to solve for x. Let's use the first equation:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
Therefore, the solution to the system of equations is x = -3 and y = 6.
Option 3, (-3, 6), is the correct answer.