which equation has a graph perpendicular to the graph of 7x=14y-8 ?
To find the equation of a line that is perpendicular to the given line, we need to determine the slope of the given line first.
Given the equation 7x = 14y - 8, we can rewrite it in slope-intercept form (y = mx + b) by rearranging the equation:
14y = 7x + 8
y = (7/14)x + 8/14
y = (1/2)x + 4/7
The slope of the given line is 1/2.
For a line to be perpendicular to this line, it must have a slope that is the negative reciprocal of 1/2.
The negative reciprocal of 1/2 is -2.
Therefore, the equation of a line perpendicular to 7x = 14y - 8 has a slope of -2.
The equation of a line with a slope of -2 can be written as y = -2x + b, where b is the y-intercept of the line.
Thus, the equation of the line perpendicular to 7x = 14y - 8 is y = -2x + b, where b is a constant.