what equation could the architect enter to represent a second beam whose graph will pass through the corner at (0, 10) and be parallel to existing beam? give your answer in slope-intercept form.
To represent a second beam that passes through the corner at (0, 10) and is parallel to the existing beam, we can use the slope-intercept form of a linear equation: y = mx + b.
Since the new beam is parallel to the existing beam, it will have the same slope. Thus, we need to determine the slope of the existing beam.
Let's assume the equation of the existing beam is y = mx + b1. We're given that the existing beam passes through the corner (0, 0). Therefore, substituting these values into the equation, we get: 0 = m(0) + b1, which simplifies to b1 = 0.
Thus, the equation of the existing beam can be written as: y = mx.
Since the new beam is also parallel, it will have the same slope, m.
Now, we're given that the new beam passes through the corner (0, 10). Substituting these values into the equation, we get: 10 = m(0) + b.
Simplifying this equation, we find b = 10.
Therefore, the equation representing the second beam in slope-intercept form (y = mx + b) is y = mx + 10.