Jerrica is packing a box that can hold at most 65 pounds. She starts by putting a container in the box that weighs 26 pounds. She plans to fill the rest of the box with books. Each book she places in the box weighs 1.3 pounds. Write an inequality for the number of books Jerrica can put in the box, and describe the solutions.(2 points)

Question

Jerrica is packing a box that can hold at most 65 pounds. She starts by putting a container in the box that weighs 26 pounds. She plans to fill the rest of the box with books. Each book she places in the box weighs 1.3 pounds. Write an inequality for the number of books Jerrica can put in the box, and describe the solutions.(2 points)

x+
≤
, where x is the number of books Jerrica can put in the box. Jerrica can put at most
books in the box.

Answer 1

Jerrica can put at most 30 books in the box.

Answer 2

The inequality is:

1.3x + 26 ≤ 65

Solving this inequality will give the maximum number of books, x, that Jerrica can put in the box. The solutions will range from 0 books to the maximum number of books that can fit in the box.

Answer 3

Jerrica can put at most ___

books in the box.

Answer 4

To write an inequality for the number of books Jerrica can put in the box, we need to consider the weight constraint.

First, we know that the weight of the container is 26 pounds. So, the total weight Jerrica can put in the box is 65 - 26 = 39 pounds.

Next, we need to determine the weight of each book. Since each book weighs 1.3 pounds, the total weight of the books can be represented as 1.3x, where x is the number of books.

To fulfill the weight constraint, the total weight of the books should be less than or equal to 39 pounds. Therefore, the inequality is:

1.3x ≤ 39

Simplifying the inequality, we can divide both sides by 1.3:

x ≤ 30

So, Jerrica can put at most 30 books in the box. The solutions to the inequality are all non-negative integers that satisfy the condition that the number of books (x) is less than or equal to 30.