Use the properties of operations to add 9(k+13)+10(12k−1).(1 point)
Responses
14k−7
14 k minus 7
14k+13
14 k plus 13
14k−23
14 k minus Start Fraction 2 over 3 End Fraction
1912k−23
19(12k) - 23
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My apologies for the mistake. Let's correct it:
To simplify 9(k + 13) + 10(12k - 1), we can distribute the coefficients to each term within the parentheses:
9(k) + 9(13) + 10(12k) + 10(-1)
This simplifies to:
9k + 117 + 120k - 10
= 9k + 120k + 117 - 10
= 129k + 107
To add the expression 9(k+13)+10(12k−1), we can distribute the 9 and the 10 to each term inside the parentheses.
First, distribute the 9 to both terms inside the first set of parentheses:
9(k+13) = 9k + 9(13) = 9k + 117
Then, distribute the 10 to both terms inside the second set of parentheses:
10(12k−1) = 10(12k) + 10(-1) = 120k - 10
Now, we have:
9k + 117 + 120k - 10
To combine like terms, we add the coefficients of the k terms and also add the constant terms:
9k + 117 + 120k - 10 = (9k + 120k) + (117 - 10) = 129k + 107
Therefore, the simplified expression is 129k + 107.