Use the properties of operations to add 9(k+13)+10(12k−1) .(1 point)
Responses
1912k−23
19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction
14k−23
14 k minus Start Fraction 2 over 3 End Fraction
14k+13
14 k plus 13
14k−7
The correct response is 1912k - 23. To solve this expression, you can use the distributive property to multiply each term inside the parentheses by the corresponding coefficient outside the parentheses:
9(k + 13) + 10(12k - 1)
= 9k + 117 + 120k - 10
= (9k + 120k) + (117 - 10)
= 129k + 107
= 1912k - 23 (simplified expression)
not an answer
I apologize for the confusion. Let's try solving the expression step by step to get the correct answer.
9(k + 13) + 10(12k - 1)
= 9k + 9(13) + 10(12k) - 10(1) (using the distributive property)
= 9k + 117 + 120k - 10
= (9k + 120k) + (117 - 10) (combining like terms)
= 129k + 107
Therefore, the correct answer is 129k + 107.
in a fractio
I apologize for the confusion. Let's represent the answer as a single fraction.
Starting with the expression 9(k + 13) + 10(12k - 1), we can distribute the coefficients to the terms inside the parentheses:
= 9k + 9(13) + 10(12k) - 10(1)
Simplifying the expressions inside the parentheses gives:
= 9k + 117 + 120k - 10
Next, combining like terms by adding or subtracting coefficients gives:
= 129k + 107
Therefore, the answer can be represented as the fraction 129k + 107.
To add 9(k+13) + 10(12k-1), you can distribute the numbers outside the parentheses to the terms inside:
= 9k + 9(13) + 10(12k) - 10(1)
= 9k + 117 + 120k - 10
Now, combine like terms:
= 9k + 120k + 117 - 10
= 129k + 107
To add 9(k+13) and 10(12k-1), you can use the distributive property of multiplication over addition.
First, distribute the 9 to each term inside the parentheses:
9(k) + 9(13)
This simplifies to 9k + 117.
Next, distribute the 10 to each term inside the other set of parentheses:
10(12k) + 10(-1)
This simplifies to 120k - 10.
Now, you can add the two simplified expressions together:
(9k + 117) + (120k - 10)
Combine like terms:
9k + 120k + 117 - 10
Combine the constants:
9k + 120k + 107
Finally, combine the variable terms:
(9k + 120k) + 107
129k + 107
So the sum of 9(k+13) and 10(12k-1) is 129k + 107.