a line has a slope -5/3 through which two points could this line pass
To find two points through which a line with a slope of -5/3 could pass, we need to consider any two pairs of x and y values that satisfy the equation of the line.
The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
From the given slope -5/3, we have m = -5/3. Let's assume y-intercept b as 0 for simplicity.
Plug in the known values into the equation: y = (-5/3)x + 0
Next, we can choose any two pairs of x and y that make this equation true.
Option 1:
Let's choose x = 0:
y = (-5/3)(0) + 0
y = 0
So, one point is (0, 0).
Option 2:
Let's choose x = 3:
y = (-5/3)(3) + 0
y = -5
So, another point is (3, -5).
Therefore, the line with a slope of -5/3 can pass through the points (0, 0) and (3, -5).