A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t = 2 by using the formula 75 - 16t ^ 2 where t is time in seconds. (1 point)
To find the number of feet the diver is above the ocean in 2 seconds, substitute t = 2 into the formula 75 - 16t^2.
75 - 16(2)^2 = 75 - 16(4) = 75 - 64 = <<75-16*4=11>>11 feet.
The diver is 11 feet above the ocean in 2 seconds. Answer: \boxed{11}.