subtract 11Root19 - 5Root19
the difference is
6√19
multiply ( 5√19 ) ( 6√2 ) give an exact answer
To multiply the given expressions, we can multiply the numbers outside the square roots and then multiply the numbers inside the square roots.
5√19 * 6√2
= (5 * 6) * (√19 * √2)
= 30√(19 * 2)
= 30√38
So, the exact answer is 30√38.
divide root95/3root5 provide an exact answer
To divide the given expressions, we can simplify the division by multiplying the numerator and denominator by the conjugate of the denominator (√5).
√95 / (3√5)
= √95 * √5 / (3√5 * √5)
= √(95 * 5) / (3 * √(5 * 5))
= √475 / 3√25
= √475 / 3 * 5
= √475 / 15
So, the exact answer is √475 / 15.
what is the irrational square root, Root63 rewritten as the product of an integer and another irrational square root in simplest form
To rewrite √63 as the product of an integer and another irrational square root in simplest form, we need to find the largest perfect square that divides evenly into 63.
The largest perfect square that divides evenly into 63 is 9, which is 3 * 3.
√63 = √(9 * 7)
We can now write it as:
√(9 * 7) = √9 * √7
Simplifying, we have:
√9 * √7 = 3 * √7
So, √63 can be rewritten as 3√7.
what is the irrational cube root 3^Root81 rewritten as a product of an integer and another irrational cube root?
To rewrite 3^(√81) as a product of an integer and another irrational cube root, we need to simplify the expression (√81).
√81 is equal to 9, so the expression becomes:
3^9
Now, we can rewrite 3^9 as the product of an integer and another irrational cube root by finding the largest perfect cube that divides evenly into 9.
The largest perfect cube that divides evenly into 9 is 1, which is 1 * 1 * 1.
So, 3^9 can be rewritten as:
3^9 = (3^3)^3
Simplifying further, we have:
(3^3)^3 = 27^3
Therefore, the expression 3^(√81) can be rewritten as 27^3, which is the product of an integer (27) and another irrational cube root.
find the cubic root of 135
3 3^√5
5 3^√27
3^√5
3√5