Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup. (1 point)
104+16x=92+13x ; x=4
92+16x=104+13x ; x=6
92+16x=104+13x ; x=4
92−16x=104−13x ; x=−4
104 + 13x = 92 + 16x
Subtract 13x from both sides:
104 = 92 + 3x
Subtract 92 from both sides:
12 = 3x
Divide both sides by 3:
x = 4
Therefore, the two machines will have filled the same number of cans of soup in 4 minutes.