Kevin measured a line to be 11.6 inches long. If the actual length of the line is 10.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?
The percent error can be found by subtracting the actual length from the measured length, dividing by the actual length, and then multiplying by 100 percent.
$\text{Percent Error} = \frac{11.6 - 10.3}{10.3} \cdot 100\% = \frac{1.3}{10.3} \cdot 100\% = 12.6\% \approx \boxed{12.6\%}$.