Step by step bot answer this please Ashortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96
To find the distance the shortstop needs to throw the ball, we can use the Pythagorean theorem. In this case, we have a right triangle with one side measuring 34 feet (the distance from second base to the shortstop) and one side measuring 35 feet (the distance from the shortstop to third base). We want to find the length of the hypotenuse, which represents the distance the shortstop needs to throw the ball (from second base to first base).
Using the Pythagorean theorem:
hypotenuse^2 = side1^2 + side2^2
Let's substitute the given values:
hypotenuse^2 = 34^2 + 35^2
hypotenuse^2 = 1156 + 1225
hypotenuse^2 = 2381
To find the length of the hypotenuse, we need to take the square root of both sides:
hypotenuse = sqrt(2381)
hypotenuse ≈ 48.8 (rounded to the nearest 10th)
Therefore, the shortstop needs to throw the ball approximately 48.8 feet (rounded to the nearest 10th) from second base to first base.
step by step bot give me the right answer
Apologies for the confusion. Let's solve the problem step by step:
1. Given information:
- Distance from second base to shortstop: 34 feet
- Distance from shortstop to third base: 35 feet
- Distance from first base to second base: 90 feet
2. We can visualize this situation by drawing a diagram with a right triangle (with the shortstop as the right angle) and label the sides:
- Side 1: Distance from second base to shortstop = 34 feet
- Side 2: Distance from shortstop to third base = 35 feet
- Hypotenuse: Distance the shortstop needs to throw - this is what we need to find
3. Using the Pythagorean theorem, we know that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
hypotenuse^2 = side1^2 + side2^2
4. Substitute the given values into the Pythagorean theorem equation:
hypotenuse^2 = 34^2 + 35^2
hypotenuse^2 = 1156 + 1225
hypotenuse^2 = 2381
5. Solve for hypotenuse by taking the square root of both sides:
hypotenuse ≈ sqrt(2381)
hypotenuse ≈ 48.8357
6. Round the answer to the nearest 10th:
The shortstop needs to throw the ball approximately 48.8 feet (rounded to the nearest 10th) from second base to first base.
To find the distance the shortstop needs to throw the ball from second base to first base, we can use the Pythagorean theorem because we have a right triangle formed by the three bases.
Step 1: Identify the lengths of the sides of the right triangle:
- The distance from second base to third base is given as 35 feet.
- The distance from third base to first base is given as 90 feet.
- The distance from second base to first base, which we need to find, can be represented as "x" feet.
Step 2: Apply the Pythagorean theorem:
According to the Pythagorean theorem, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the distance from second base to first base.
Using the theorem: c² = a² + b²
where c is the hypotenuse, a and b are the other two sides:
x² = 35² + 90²
x² = 1225 + 8100
x² = 9325
Step 3: Solve for x:
Taking the square root of both sides, we get:
x = √9325
Calculating the square root (√9325), we find that x is approximately 96.5 feet.
Therefore, the shortstop needs to throw the ball approximately 96.5 feet from second base to first base, rounded to the nearest tenth.