A shortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96.1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9

Question

A shortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96.1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9

Answer 1

To solve this problem, we can use the Pythagorean theorem.

Let the distance from the shortstop to first base be x. Then, the distance from second base to first base is x + 34 feet.

Using the Pythagorean theorem, we have:

(x + 34)^2 = 35^2 + x^2

Expanding and simplifying the equation, we get:

x^2 + 68x + 1156 = 1225 + x^2

68x = 69

x ≈ 1

Therefore, the shortstop needs to throw the ball approximately 1 foot to reach first base.