A shortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90

Question

A shortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90

Answer 1

To find the distance the shortstop needs to throw the ball to first base, we can use the Pythagorean theorem.

Let's consider the distance from the shortstop to second base as the base of a right triangle and the distance from the shortstop to first base as the height. We can calculate the hypotenuse, which represents the distance between the second base and first base.

Using the Pythagorean theorem, we have:

Distance^2 = Base^2 + Height^2

Distance^2 = 34^2 + 90^2

Distance^2 = 1156 + 8100

Distance^2 = 9256

Distance ≈ √9256

Distance ≈ 96.1 feet

Therefore, the shortstop needs to throw the ball approximately 96.1 feet to first base.