A shortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer tot eh nearest tenth
To find the distance the shortstop needs to throw the ball, we can use the Pythagorean theorem.
The distance from second base to first base is the hypotenuse of a right triangle, with the distance from the shortstop to second base as one side and the distance from the shortstop to first base as the other side.
Using the Pythagorean theorem, we can find the distance she needs to throw as follows:
Distance^2 = (Distance from shortstop to second base)^2 + (Distance from shortstop to first base)^2
Distance^2 = 34^2 + 90^2
Distance^2 = 1156 + 8100
Distance^2 = 9256
Distance ≈ √9256
Distance ≈ 96.15 feet
Therefore, the shortstop needs to throw the ball approximately 96.15 feet to first base.
Wrong
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To find the distance the shortstop needs to throw the ball, we can use the Pythagorean theorem.
The distance from second base to first base is the hypotenuse of a right triangle, with the distance from the shortstop to second base as one side and the distance from the shortstop to first base as the other side.
Using the Pythagorean theorem:
Distance^2 = (Distance from shortstop to second base)^2 + (Distance from shortstop to first base)^2
Distance^2 = 34^2 + 90^2
Distance^2 = 1156 + 8100
Distance^2 = 9256
Distance ≈ √9256
Distance ≈ 96.1 feet (rounded to the nearest tenth)
Therefore, the shortstop needs to throw the ball approximately **96.1 feet** to first base.
To find the distance the shortstop needs to throw the ball to first base, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, the base path between second base and third base forms a right triangle with the throw to first base.
Let's label the distance the shortstop is from second base as side A, the distance from second base to first base as side B, and the distance the shortstop needs to throw the ball to first base as the hypotenuse C.
Side A = 34 feet
Side B = unknown
Side C = unknown
Using the Pythagorean theorem, we can solve for side B (the distance from second base to first base).
C^2 = A^2 + B^2
B^2 = C^2 - A^2
To find the value of B, we substitute the known values into the equation:
B^2 = C^2 - A^2
B^2 = (distance the shortstop needs to throw the ball)^2 - 34^2
Now, we can calculate B by taking the square root of both sides of the equation:
B = √((distance the shortstop needs to throw the ball)^2 - 34^2)
Let's assume the distance the shortstop needs to throw the ball is X feet:
B = √(X^2 - 34^2)
Finally, to get the answer to the question, you can substitute the value of X with the distance calculated and then round the result to the nearest tenth.