A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75−16t2 , where t is time in seconds.
To find the number of feet the diver is above the ocean in 2 seconds, we need to evaluate the expression: 75 - 16(2)^2.
First, we simplify the exponent: 2^2 = 4.
Next, we multiply the simplified exponent by 16: 16 * 4 = 64.
Finally, we subtract the result from 75: 75 - 64 = <<75-64=11>>11.
Therefore, the diver is 11 feet above the ocean after 2 seconds.