Solve the factored quadratic equation (19x−3)(9+x)=0%0D%0A(%0D%0A19%0D%0A%0D%0A−%0D%0A3%0D%0A)%0D%0A(%0D%0A9%0D%0A+%0D%0A%0D%0A)%0D%0A=%0D%0A0%0D%0A
To solve the factored quadratic equation (19x−3)(9+x)=0, we set each factor equal to zero and solve for x:
Setting 19x−3=0:
Adding 3 to both sides, we get:
19x=3
Dividing both sides by 19, we get:
x=3/19
Setting 9+x=0:
Subtracting 9 from both sides, we get:
x=-9
Therefore, the solutions to the equation are x=3/19 and x=-9.