a minor league baseball plays 79 games in a season if the team won 13 more than twice as many games as they lost, how many wins and losses did the team have
Let's assume the number of games the team lost is x.
Twice as many games as the team lost is 2x.
13 more than twice as many games as the team lost is 2x + 13.
The number of games the team won is 2x + 13.
The total number of games the team played is the sum of games won and games lost, which is 2x + 13 + x = 79.
Combining like terms, we get 3x + 13 = 79.
Subtracting 13 from both sides, we get 3x = 66.
Dividing both sides by 3, we get x = 22.
Therefore, the team lost 22 games and won 2(22) + 13 = 57 games.