To find the number of feet the diver is above the ocean at 2 seconds, we need to evaluate the formula 75 - 16t2 squared, where t is the time in seconds.
To find the number of feet the diver is above the ocean at 2 seconds, we need to evaluate the formula 75 - 16t^2, where t is the time in seconds.
So, substituting t = 2 into the formula, we get:
75 - 16(2)^2
75 - 16(4)
75 - 64
11
Therefore, the number of feet the diver is above the ocean at 2 seconds is 11 feet.
To find the number of feet the diver is above the ocean at 2 seconds, plug in the value of t = 2 into the given formula:
75 - 16 * (2^2)
First, solve inside the parentheses:
2^2 = 4
Now substitute this value into the formula:
75 - 16 * 4
Multiply:
75 - 64
Subtract:
11
Therefore, the diver is 11 feet above the ocean at 2 seconds.
To find the number of feet the diver is above the ocean at 2 seconds, we need to substitute t = 2 into the given formula:
h(t) = 75 - 16t^2
Replacing t with 2, we get:
h(2) = 75 - 16(2)^2
Simplifying:
h(2) = 75 - 16(4)
h(2) = 75 - 64
h(2) = 11
Therefore, the diver is 11 feet above the ocean at 2 seconds.