To find the number of feet the diver is above the ocean at 2 seconds, we need to evaluate the formula 75 - 16t^2, where t is the time in seconds.
To find the number of feet the diver is above the ocean at 2 seconds, we substitute t = 2 into the formula 75 - 16t^2:
75 - 16(2)^2 = 75 - 16(4) = 75 - 64 = <<75-16*4=11>>11 feet.
Therefore, the diver is 11 feet above the ocean at 2 seconds.
To find the number of feet the diver is above the ocean at 2 seconds, you need to substitute the value of t as 2 in the given formula 75 - 16t^2.
Step 1: Start with the formula 75 - 16t^2.
Step 2: Substitute t as 2 in the formula, which gives you 75 - 16(2)^2.
Step 3: Simplify the expression inside the parentheses, so you have 75 - 16(4).
Step 4: Simplify the expression inside the parentheses further, resulting in 75 - 64.
Step 5: Calculate 75 - 64, which gives you a final answer of 11.
Therefore, at 2 seconds, the diver is 11 feet above the ocean.
To find the number of feet the diver is above the ocean at 2 seconds, plug in the value of t = 2 into the formula 75 - 16t^2.
Step 1: Substitute the value of t into the formula.
75 - 16(2)^2
Step 2: Simplify the expression inside the parentheses.
75 - 16(4)
Step 3: Perform the multiplication.
75 - 64
Step 4: Subtract the two values.
75 - 64 = 11
Therefore, the diver is 11 feet above the ocean at 2 seconds.